Question #a32cf

1 Answer
P dilip_k
Mar 11, 2016

See below

Explanation:

2C_8H_18+25O_2=16CO_2+18H_2O

you can remember following also
C_xH_y +(x+y/4)O_2=xCO_2+y/2H_2O

=>2C_xH_y +(2x+y/2)O_2=2xCO_2+yH_2O

Oxidation Number Method
C_8 H_18+O_2->CO_2+H_2O
change in oxidation no of C =>-9/4->+4=25/4unit oxidation
change in oxidation no of O =>0->-2=2unit Reduction
ratio of no of C and O =2:25/4=8:25
ratio of no of C_8H18 and O =1:25
ratio of no of C_8H18 and O =2:50
ratio of no of C_8H18 and O_2 =2:25

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