Question #3aee6

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Question #3aee6

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Answer 1 · 2016-03-28T23:03:44

$60.1 g$ $"60.1 g"$

Explanation:

You can think about a substance's density as being a conversion factor between mass and volume.

More specifically, a substance's density will tell the mass of that substance that occupies one unit of volume.

In this case, 1,3-cycloheptadiene is said to have a density of ${0.868 g mL}^{- 1}$ $"0.868 g mL"^(-1)$ . The volume is expressed in milliliters, which means that one unit of volume would correspond to $1 mL$ $"1 mL"$ .

So, you know that every $1 mL$ $"1 mL"$ of 1,3-cycloheptadiene has a mass of $0.868 g$ $"0.868 g"$ , which means that $69.2 mL$ $"69.2 mL"$ will have a mass of

$69.2 mL \cdot density      \frac{0.868 g}{1 mL} = ∣ ∣ ∣ ∣ ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ \frac{a}{a} 60.1 g \frac{a}{a} ∣ ∣ - -------- - \to$ $69.2 color(red)(cancel(color(black)("mL"))) * overbrace("0.868 g"/(1color(red)(cancel(color(black)("mL")))))^(color(purple)("density")) = color(green)(|bar(ul(color(white)(a/a)"60.1 g"color(white)(a/a)|))) ->$ rounded to three sig figs.

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Question #3aee6

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