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Question #2879f

1 Answer

Apr 9, 2016

$1.91 k g m^{- 3}$ $1.91kgm^-3$

Explanation:

Density, $ρ$ $rho$ , is $\frac{mass}{volume}$ $"mass"/"volume"$ , given in the units $\frac{k g}{m^{3}}$ $(kg)/m^3$ or $k g m^{- 3}$ $kgm^-3$

$ρ = \frac{42}{22} \frac{k g}{m^{3}} = 1.91 k g m^{- 3}$ $rho = 42/22 (kg)/m^3 = 1.91kgm^-3$

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