How do you solve the system of equations: $2x-y=6$ , $4x-2y=-3$ ?

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Answer 1 · 2016-05-06T17:53:14

These simultaneous equations have no solution.

If you multiply both sides of the first equation by $2$ then you get:

$4x-2y=12$

The second equation gives us:

$4x-2y=-3$

SInce $12!=-3$ these two equations cannot be satisfied simultaneously.

The graphs of these two equations are a pair of parallel lines and do not intersect:

graph{(4x-2y-12)(4x-2y+3) = 0 [-10, 10, -5, 5]}

How do you solve the system of equations: 2x-y=62x-y=6, 4x-2y=-34x-2y=-3 ?