Question #a28ee

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Question #a28ee

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Answer 1 · 2016-07-08T14:38:34

$10 s$ $10s$

Explanation:

Speed of train $= 10 m s^{- 1}$ $=10ms^-1$ , due north
Speed of bird $= 5 m s^{- 1}$ $=5ms^-1$ , due south
Relative speed of bird with respect to train $= 5 - (- 10)$ $=5-(-10)$
$= 15 m s^{- 1}$ $=15ms^-1$
Length of train $= 150 m$ $=150m$
We know that $Time = \frac{Distance traveled}{Speed}$ $"Time" ="Distance traveled"/"Speed"$
In the given problem

$Time = \frac{150}{15} = 10 s$ $"Time" =150/15=10s$
For relative speed.

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Question #a28ee

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