Simplify $(cscxcosx)/(tanx+cotx)$ ?

Question

6229 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-02T12:21:14

Please see below.

$(cscxcosx)/(tanx+cotx)$

= $(cscxcosx)/(sinx/cosx+cosx/sinx)$

= $(cscxcosx)/((sin^2x+cos^2x)/(cosxsinx))$

= $(cscxcosx)/(1/(cosxsinx))$

= $cscxcosx xxcosxsinx$

= $cos^2x xx cscxsinx$

= $cos^2x xx1=cos^2x$

Simplify (cscxcosx)/(tanx+cotx)(cscxcosx)/(tanx+cotx)?