Question #200ab

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Answer 1 · 2016-05-02T21:25:32

see below

Left Side $= cos^4x (1+sin^4x/cos^4x)$

$=cos^4x xx (cos^4x+sin^4x)/cos^4x$

$=cos^4x+sin^4x$

$= cos^2x cos^2x+ sin^2x sin^2x$

$=(1-sin^2x)cos^2x+(1-cos^2x)sin^2x$

$=cos^2x-sin^2xcos^2x+sin^2x-sin^2xcos^2x$

$=cos^2x+sin^2x-2sin^2xcos^2x$

$=1-2sin^2xcos^2x$

$=$ Right Side