Question #7e002

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Question #7e002

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Answer 1 · 2016-04-28T10:41:08

$2 N a C l + H_{2} S O_{4} = N a_{2} S O_{4} + 2 H C l$ $color(red)(2)NaCl + H_2SO_4 = Na_2SO_4+color(red)(2)HCl$

Explanation:

Since we have $N a_{2} S O_{4}$ $Na_color(red)(2)SO_4$ on the right side
the left side must have a multiple of $2$ $color(red)(2)$ $N a C l$ $NaCl$ 's

Trying the minimum of $2 N a C l$ $color(red)(2)NaCl$ on the left implies we will need to have a multiple of $2 C l$ $color(red)(2)color(white)(" ")Cl$ 's in $H C l$ $HCl$ on the right;

but the $H_{2}$ $H_color(red)(2)$ in the $H_{2} S O_{4}$ $H_2SO_4$ on the left provides the $2 H$ $color(red)(2) H$ 's needed for $2 H C l$ $color(red)(2)HCl$ to work out.

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Question #7e002

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