Solve #10^(12x+2) = (10^10)^(2x-1)# ? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Cesareo R. Jul 10, 2016 #x = 3/2# Explanation: #log_{10}(12x+2)=log_{10}((2x-1)cdot 10)->12x+2=10(2x-1)# Solving for #x# gives #x = 3/2# which is feasible Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 982 views around the world You can reuse this answer Creative Commons License