Question #81259 Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Andrea S. May 1, 2017 y = x/(sqrt(1-x^2) Explanation: y = tan(arcsin x) Pose t = arcsin x so that sint = x We have then: cost = sqrt (1-x^2) and: tant = sint/cost = x/(sqrt(1-x^2) Then: y = tan(arcsin x) = tan t = x/(sqrt(1-x^2) Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1296 views around the world You can reuse this answer Creative Commons License