Question #2a02f

1 Answer
Alan P.
May 10, 2016

There is insufficient information to give a complete answer to this question.

Explanation:

Without knowing the cross-sectional area of the measuring cylinder
we can not calculate the volume of the stone and therefore we can not calculate the stone's density.

If the cross-sectional area of the measuring cylinder is a" cm"^2a cm2
then the volume of the stone would be
color(white)("XXX") (68-40)" cm" xx a " cm"^3 = 28a " cm"^3XXX(68−40) cm×a cm3=28a cm3
and its density would be
color(white)("XXX")(50" grams")/(28a"cm"^3)XXX50 grams28acm3

color(white)("XXX")=25/(14a) " gm/cubic cm"XXX=2514a gm/cubic cm

Related questions
See all questions in Density
Impact of this question
1690 views around the world
You can reuse this answer
Creative Commons License