Question #8a7b6 Calculus Introduction to Integration Integrals of Rational Functions 1 Answer Eddie Sep 28, 2016 =−15cos5x+C Explanation: ∫sin5xdx =∫ddx(−15cos5x)dx =−15cos5x+C Answer link Related questions How do you integrate x+1x2+2x+1? How do you integrate x1+x4? How do you integrate dx2√x+2x? What is the integration of 1x? How do you integrate 1+x1−x? How do you integrate 2x3−3x2+x+1−2x+1? How do you find integral of (secxtanxsecx−1)dx? How do you integrate 6x5−2x4+3x3+x2−x−2x3? How do you integrate (4x2−1)2x3dx? How do you integrate x+3√xdx? See all questions in Integrals of Rational Functions Impact of this question 1571 views around the world You can reuse this answer Creative Commons License