Question

Question #d6aae

Answer 1

`42.4%`

Explanation:

Let an object of mass `m` has initial momentum `p_i`
Kinetic energy `KE_i=1/2p_i^2/m`
After collision let final momentum be `p_f`
Therefore kinetic energy `KE_f=1/2p_f^2/m` and
Where `=p_f` is Final momentum.
Using given `%` age of kinetic energy we have

`18%" of "KE_i=KE_f`
`=>0.18xx1/2p_i^2/m=1/2p_f^2/m`
`=>0.18xxp_i^2=p_f^2`
Taking square root of both sides we get
`0.424xxp_i=p_f`, rounded to three decimal places
Momentum is `42.4%`