Question #b5198

1 Answer
Joel Kindiak
Jun 6, 2016

dy/dx = (x-1)/(2x ln 5)

Explanation:

First, simplify the given expression.

y=log_25 (e^x)-log_5 (x^(1/2))=ln (e^x)/(2ln5)-1/2 (ln x / ln 5) = 1/(2 ln5)(x-ln x)

dy/dx = 1/(2ln5) (1-1/x) = (x-1)/(2x ln 5)

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