How do you balance the equation $2 C_{3} H_{6} O_{3} + 3 O_{2} \to 6 C O_{2} + 6 H_{2} O$ $2C_3H_6O_3+3O_2->6CO_2+6H_2O$ ?

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Answer 1 · 2016-07-02T19:25:43

$2 C_{3} H_{6} O_{3} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O$ $2C_3H_6O_3+6O_2->6CO_2+6H_2O$

The given equation is nearly balanced:

$2 C_{3} H_{6} O_{3} + 3 O_{2} \to 6 C O_{2} + 6 H_{2} O$ $2C_3H_6O_3+3O_2->6CO_2+6H_2O$

Counting the elements on each side, we have:

$6 \times C$ $6xxC$ on both sides.
$12 \times H$ $12xxH$ on both sides.
$12 \times O$ $12xxO$ on the left hand side, $18 \times O$ $18xxO$ on the right hand side.

So we just need to add $6 \times O = 3 O_{2}$ $6xxO = 3O_2$ on the left hand side to balance the equation:

$2 C_{3} H_{6} O_{3} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O$ $2C_3H_6O_3+6O_2->6CO_2+6H_2O$

How do you balance the equation 2C3H6O3+3O2→6CO2+6H2O2C_3H_6O_3+3O_2->6CO_2+6H_2O ?