Question #edd7a

Question

2533 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-09T04:32:10

$=500 u_d$

$"New unit of mass " (u_m )=20g"$

$"New unit of length " (u_l )=5cm$

$"New unit of volume " (u_v )=u_l^3=(5cm)^3=125cm^3$

$"New unit of density " u_d=(u_m/u_v )=(20g)/(125cm^3)=4/25xxg/(cm^3)$

$"So " 1g/(cm^3)=25/4 u_d$

$"So the density in new unit"$

$= 25/4xx" Value of Density in old unit"$

$=25/4xx80=500 u_d$