Question #c89c1

1 Answer
Stefan V.
Jul 14, 2016

"5.99 g"5.99 g

Explanation:

As you can see, the density of aluminium is said to be equal to "2.70 g"2.70 g per "1 mL"1 mL. This tells you that every milliliter of aluminium has a mass of "2.70 g"2.70 g.

Since you're dealing with more than "1 mL"1 mL, you can expect the mass of the sample to be bigger than "2.70 g"2.70 g. More specifically, the mass of the sample will be

2.22 color(red)(cancel(color(black)("mL"))) * overbrace("2.70 g"/(1color(red)(cancel(color(black)("mL")))))^(color(blue)("the density of Al")) = "5.994 g"

The answer must be rounded off to three sig figs, the number of sig figs you have for the volume of the sample

"mass of sample" = color(green)(|bar(ul(color(white)(a/a)color(black)("5.99 g")color(white)(a/a)|)))

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