Question #24930

Question

1262 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-05T14:03:44

Method-I

$6 x^{3} + 3 x^{2} y - 2 x y - y^{2}$ $6x^3+3x^2y-2xy-y^2$

$= 3 x^{2} (2 x + y) - y (2 x + y)$ $=3x^2(2x+y)-y(2x+y)$

$= (2 x + y) (3 x^{2} - y)$ $=(2x+y)(3x^2-y)$

Method-II

$6 x^{3} + 3 x^{2} y - 2 x y - y^{2}$ $6x^3+3x^2y-2xy-y^2$

$= 6 x^{3} - 2 x y + 3 x^{2} y - y^{2}$ $=6x^3-2xy+3x^2y-y^2$

$= 2 x (3 x^{2} - y) + y (3 x^{2} - y)$ $=2x(3x^2-y)+y(3x^2-y)$

$= (2 x + y) (3 x^{2} - y)$ $=(2x+y)(3x^2-y)$