Question #ff82b

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Answer 1 · 2016-11-15T09:45:51

$sintheta=-3/5,180 < theta <270$

The angle $theta$ lies in the third quadrant.

Where

$costheta,sectheta and csctheta-> -ve$

$and tantheta and cottheta->+ve$

So

$csctheta=-5/3$
$costheta=-sqrt(1-sin^2theta)=sqrt(1-9/25)=-4/5$

$sectheta=-5/4$

$tantheta=sintheta/costheta=(-3/5)/(-4/5)=3/4$

$cottheta=4/3$