What is $ρ_{titanium}$ $rho_"titanium"$ in $l b \cdot {inch}^{- 3}$ $lb*"inch"^-3$ ?

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Answer 1 · 2016-09-08T17:04:24

You want the density of titanium of metal in $l b \cdot {inch}^{- 3}$ $lb*"inch"^-3$ ?

$ρ_{titanium metal}$ $rho_"titanium metal"$ $=$ $=$ $4.51 \cdot g \cdot c m^{- 3}$ $4.51*g*cm^-3$

There are $454 \cdot g \cdot l b^{- 1}$ $454*g*lb^-1$ , and $2.54 \cdot c m \cdot {inch}^{- 1}$ $2.54*cm*"inch"^-1$ .

$ρ_{titanium metal}$ $rho_"titanium metal"$ $=$ $=$ $\frac{Mass}{Volume}$ $"Mass"/"Volume"$

$=$ $=$ $4.51*cancelgxx1/(454*cancelg*lb^-1)xx1/(cancel(cm^3)xx(2.54*cancel(cm)*"inch"^-1)^3)$

$=$ $0.163*lb*"inch"^-3$ ??

I think I've got this right; obviously you won't build a titanium structure on my say so! I would be more sanguine about my answer in $g*cm^-3$ .

What is rho_"titanium"ρtitaniumrho_"titanium" in lb*"inch"^-3lb⋅inch−3lb*"inch"^-3?