Prove that $cosB/(1-sinB)=secB+tanB$ ?

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Answer 1 · 2016-09-10T14:05:11

Please see below.

$cosB/(1-sinB)$

= $cosB/(1-sinB)xx(1+sinB)/(1+sinB)$

= $(cosB(1+sinB))/(1-sin^2B)$

= $(cosB(1+sinB))/cos^2B$

= $(1+sinB)/cosB$

= $1/cosB+sinB/cosB$

= $secB+tanB$

Prove that cosB/(1-sinB)=secB+tanBcosB/(1-sinB)=secB+tanB?