Question

Question #8380b

Answer 1

`"1.07 g/cm"^3`

Explanation:

Here's a quick way of figuring out the density of the saline solution.

Notice that the problem provides you with the density of pure water at `4^@"C"`. Use this to find the volume of pure water that has a mass of `"11.3 g"` at that temperature

`11.3 color(red)(cancel(color(black)("g"))) * "1 cm"^3/(1.00color(red)(cancel(color(black)("g")))) = "11.3 cm"^3`

Since you know that an equal volume of saline solution has a mass of `"12.g"` at `4^@"C"`, you can say that its density, `rho_"sal"`, will be equal to

`rho_"sal" = "12.1 g"/"11.3 cm"^3 = color(green)(bar(ul(|color(white)(a/a)color(black)("1.07 g/cm"^3)color(white)(a/a)|)))`

The answer is rounded to three sig figs.