Question #a1d99

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Question #a1d99

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Answer 1 · 2016-12-19T02:40:24

Impossible

Explanation:

We 'assume' that n is an integer. This means 2n is always an even integer.
The left hand side term is $- 1^{2 n}$ $-1^(2n)$ this is always equal to 1.
Or if we read the left hand term differently as $- (1^{2 n})$ $-(1^(2n))$ , then the term is always -1.
The right hand term is $1^{3}$ $1^3$ + $5^{8}$ $5^8$ which is way bigger than 1 or -1
So in both interpretations of -1^2n the question has no solution for n.

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Question #a1d99

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