Question #8466e

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Answer 1 · 2016-09-26T05:58:45

$118 \frac{km}{hr} = 118 \times \frac{1 k m}{1 h r}$ $118"km"/"hr"=118xx(1km)/(1hr)$

$= 118 \times \frac{1000 m}{60 \times 60 s}$ $=118xx(1000m)/(60xx60s)$

$= \frac{118 \times 1000}{60 \times 60} \frac{m}{s}$ $=(118xx1000)/(60xx60)m/s$

$\approx 32.7 m/s$ $~~32.7"m/s"$

Answer 2 · 2016-09-26T06:37:37

$118 km/h=37.8 m/s$ $"118 km/h=37.8 m/s"$ to three significant figures

First identify the equalities.

$1 km=1000 m$ $"1 km=1000 m"$

$1 h=3600 s$ $"1 h=3600 s"$

Multiply 118 km/h by the equalities in such a way as to cancel km/h, leaving m/s.

#(118cancel"km")/(1cancel"h")xx(1000"m")/(1cancel"km")xx(1cancel"h")/(3600"s")="32.777...m/s"="37.8 m/s"# (rounded to three significant figures)