Question

Question #44793

Answer 1

I tried this:

Explanation:

As suggested let us call `x` the number of dvds; we can write:

`10.5x+8(x+3)<120`

Let us solve for `x`;
`10.5x+8x+24<120`
`18.5x<120-24`
`18.5x<96`
`x<96/18.5`
`x<5.2`
We can consider that the number of dvds, called `x`, may be `5` while the cds will be `x+3=8`.

The costs will be:
`5×10.5=$52.5` for dvds;
`8×8=$64` for cds;
Giving a total cost of `52.5+64=$116.5` which is less than `$120`.

(Hope it helps!)