Question

10.00 ml of 0.1089 M oxalic acid neutralises 18.65 ml of sodium hydroxide solution. What is the concentration of the sodium hydroxide ?

Answer 1

`sf([NaOH]=0.1168color(white)(x)"mol/l")`

Explanation:

`sf(H_2C_2O_(4(aq))+2NaOH_((aq))rarrNa_2C_2O_(4(aq))+2H_2O_((l)))`

`sf(n_(H_2C_2O_4)=cxxv=0.1089xx10.00/1000=0.001089)`

`:.` `sf(n_(NaOH)=0.001089xx2=0.002178)`

`sf(c=n/v)`

`:.` `sf([NaOH]-=(0.002178)/(0.01865)=0.1168color(white)(x)"mol/l")`