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Answer 1 · 2016-09-27T19:40:59

$7.833 \frac{g}{c m^{3}}$ $7.833 g/(cm^3)$

As you would know, the density of an object is its mass per unit volume, and can be calculated as follows:

Density, $D$ $D$ = Total Mass of the Object, $m$ $m$ / Total Volume of the Object, $V$ $V$

Mass of the iron block, $m = 94 g$ $m= 94g$

Volume of the iron block, $V = 2 c m \cdot 3 c m \cdot 2 c m = 12 c m^{3}$ $V=2cm*3cm*2cm=12cm^3$

Density, $D = \frac{m}{V}$ $D=m/V$

$= \frac{94 g}{12 c m^{3}}$ $=(94g)/(12cm^3)$

$= 7.833 \frac{g}{c m^{3}}$ $=7.833 g/(cm^3)$