Question #94595

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Answer 1 · 2016-10-03T01:45:55

$-67$

Let the 3 consecutive integers be $-(x-1), -x, -(x+1)$
$=> -204=-(x-1+x+x+1)$
$=> -204=-3x$
$=>68=x$

$=> -(x-1)=-(68-1)=-67$
$-x=-68$
$-(x+1)=-(68+1)=-69$

$=>$ the largest of the3 consecutive integers $=-67$

Answer 2 · 2016-10-03T01:46:34

The three consecutive integers are $-69. -68, -67$
The largest is $-67$

Let $x=$ the first integer.

The second consecutive integer is $x+1$

The third consecutive integer is $x+2$

If the sum of the three integers is $-204$ ...

$x + x+1+x+2=-204$

$3x+3=-204$

$color(white)(aa)-3color(white)(aaaa)-3$

$color(white)(aa)3xcolor(white)(a^1)=-207$

$color(white)(a)(3x)/3color(white)(a^1)=-207/3$

$color(white)(a^1)xcolor(white)(aa^1)=-69$

$x+1=-68$

$x+2=-67$

The three consecutive integers are $-69. -68, -67$

The largest is $-67$