Question #489d0

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Question #489d0

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Answer 1 · 2016-10-01T05:36:30

$The net displacement ∣ ∣ ∣ \to d ∣ ∣ ∣ = 14.7 k m, 35^{\circ} South of East$ $"The net displacement " abs(vecd)=14.7km, 35^@ "South of East"$

$The East component this of displacement$ $"The East component this of displacement "$
$= {∣ ∣ ∣ \to d ∣ ∣ ∣}_{E} = 14.7 {cos 35}^{\circ} k m \approx 12 k m$ $=abs(vecd)_E=14.7cos35^@km~~12km$

$The South component this of displacement$ $"The South component this of displacement "$
$= {∣ ∣ ∣ \to d ∣ ∣ ∣}_{S} = 14.7 {sin 35}^{\circ} k m = 8.43 k m$ $=abs(vecd)_S=14.7sin35^@km=8.43km$

So it can be said that

$The North component this of displacement$ $"The North component this of displacement "$
$= {∣ ∣ ∣ \to d ∣ ∣ ∣}_{N} = - 8.43 k m$ $=abs(vecd)_N=-8.43km$

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Question #489d0

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