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Question #07cd9

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Oct 31, 2016

$sin θ = \frac{1}{2}$ $sintheta=1/2$

$\Rightarrow sin θ = sin (\frac{π}{6}) = sin (- π - \frac{π}{6})$ $=>sintheta=sin(pi/6)=sin(-pi-pi/6)$

(As $- \frac{3 π}{2} < θ < 0$ $" "-(3pi)/2 <theta < 0$ )

$\Rightarrow sin θ = sin (- \frac{7 π}{6})$ $=>sintheta=sin(-(7pi)/6)$

$\Rightarrow θ = - \frac{7 π}{6}$ $=>theta=-(7pi)/6$

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