Question

Question #ebf3f

Answer 1

It is a fact (i) that most elemental gases are DIATOMIC; it is a fact (ii) that mass is always conserved in a chemical reaction.

Explanation:

Most of the elemental gases, `O_2`, `N_2`, `F_2`, `Cl_2` are diatomic under standard conditions. The exceptions are the Noble Gases, which rarely form compounds. You simply have to know the so-called molecularity of oxygen, nitrogen, etc. Most inorganic chemists refer to these gases as `"dinitrogen"`, `"dioxygen"`, `"dihydrogen"` to avoid ambiguity.

Knowledge of the molecularity of the elemental gases would be assumed for an A level student, and it certainly would be expected of a 1st year college student.

Now chemical reactions follow experimental result; experimental result does not follow our depiction of the equation. For the reaction of oxygen and hydrogen, we know that 1/2 an equiv of dioxygen reacts with one equiv of dihydrogen under normal conditions to give one equiv of water:

`H_2(g) + 1/2O_2(g) rarr H_2O(l)` `(i)`

If I wanted to, I could double the entire equation to get rid of the half-integral coefficients.

`2H_2(g) + O_2(g) rarr 2H_2O(l)` `(ii)`

The point is that these equations are representations of chemical reality. Now these reactions certainly conserve mass: in `(i)` 18 g of dioxygen and dihydrogen combine to give 18 g of water (we would assume it to be a liquid under standard conditions!).

Given certain conditions, however, we could in fact produce hydrogen peroxide under so-called reducing conditions:

`H_2(g) + O_2(g) rarr HO-OH(l)` `(iii)`

This would be admittedly hard to do, nevertheless, we can still conceive of the reaction as a formality, and we can certainly estimate the thermodynamic parameters involved in the reaction. In the reaction `(iii)`, less energy would be evolved in the reaction because we are not completely reducing the oxygen gas, and we are only forming `2xxH-O` bonds rather than the `4xxH-O` bonds we form in `(ii)`. For another question dealing with the conservation of mass, see [here.](https://socratic.org/questions/what-is-a-balanced-chemical-equation-how-would-you-use-the-law-of-conservation-o)

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