Question

Question #929f6

Answer 1

The `Co^(2+)andPO_4^(3-)` ions will form a precipitate.

Explanation:

So we can leave out the `Cl^(-) andNa^+` ions, as they are only 'spectators', i.e. they will be left unchanged in the solution.

Since `Co` has a charge of +2 and `PO_4` has a charge of -3, we will have to take 3 of the first and 2 of the other to make charges equal (but opposite):

`3Co^(2+)(aq)+2PO_4^(3-)(aq)->Co_3(PO_4)_2(s)`