Question #8ffa7

1 Answer
Oct 14, 2016

Just expand the factorials.

(n + 1)(n) + (n + 1)(n) xx n+ 1 = (n + 2)(n + 1)(n)(n+1)(n)+(n+1)(n)×n+1=(n+2)(n+1)(n)

n^2 + n + (n^2 + n)(n + 1) = (n^2 + 3n + 2)(n)n2+n+(n2+n)(n+1)=(n2+3n+2)(n)

n^2 + n + n^3+ n^2 + n^2 + n = n^3 + 3n^2 + 2nn2+n+n3+n2+n2+n=n3+3n2+2n

n^3 + 3n^2 + 2n = n^3 + 3n^2 + 2nn3+3n2+2n=n3+3n2+2n

Hopefully this helps!