Question #54631

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Answer 1 · 2016-10-29T15:22:07

To prove :- $color(blue)(Cos^2acot^2a=cot^2a-cos^2a)$

$RHS=cot^2a-cos^2a$

$=cot^2a(1-(cos^2a)/(cot^2a))$

$=cot^2a(1-(cos^2a)/((cos^2a)/(sin^2a)))$

$=cot^2a(1-cancel(cos^2a)/cancel(cos^2a)*sin^2a)$

$=cot^2a(1-sin^2a)$

$=cot^2acos^2a=LHS$

proved