Solve y=.13x^2+20.93x+838.43y=.13x2+20.93x+838.43?

1 Answer

See below:

Explanation:

I'll assume y=.13x^2+20.93x+838.43y=.13x2+20.93x+838.43 is meant.

Let's use the quadratic formula:

x = (-b \pm sqrt(b^2-4ac)) / (2a) x=b±b24ac2a

where we have a=.13, b=20.93, c=838.43a=.13,b=20.93,c=838.43

x = (-20.93 \pm sqrt((20.93)^2-4(.13)(838.43))) / (2(.13)) x=20.93±(20.93)24(.13)(838.43)2(.13)

x = (-20.93 \pm sqrt(438.0649-435.9836)) / .26 x=20.93±438.0649435.9836.26

x = (-20.93 \pm sqrt(2.0813)) / .26 x=20.93±2.0813.26

x=(-20.93 + sqrt(2.0813)) / .26 ~=-74.95x=20.93+2.0813.2674.95

x=(-20.93 - sqrt(2.0813)) / .26 ~=-86.05x=20.932.0813.2686.05

The graph looks like this:

graph{.13x^2+20.93x+838.43[-90,-70,-5,5]}