Question #0bbd5

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Question #0bbd5

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Answer 1 · 2016-11-02T00:16:02

The slope is $2$ $2$ and the $y$ $y$ -intercept is $- 3$ $-3$ .

Explanation:

The slope-intercept form of the equation of a line is $y = m x + b$ $y=mx+b$ . A line with this equation has a slope of $m$ $m$ and a $y$ $y$ -intercept of $b$ $b$ .

(For why this is the case, consider that increasing $x$ $x$ by $1$ $1$ increases $y$ $y$ by $m$ $m$ , making $\frac{m}{1} = m$ $m/1=m$ the slope, and setting $x = 0$ $x=0$ shows us that the $y$ $y$ -intercept is at $(0, b)$ $(0, b)$ )

For the given equation, we use algebraic manipulation to put it into slope-intercept form.

$y - 2 x = - 3$ $y-2x = -3$

$\Rightarrow y - 2 x + 2 x = - 3 + 2 x$ $=> y-2x+2x = -3+2x$

$:. y = 2x-3$

As this is slope-intercept form with $m=2$ and $b=-3$ , the slope is $2$ and the $y$ -intercept is $-3$ .

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