Question #f34ef

1 Answer
seol
Nov 15, 2016

7^(2^x)=\approx2.08649

Explanation:

7^(-x)=4
1/7^x=4
1/4=7^x
log_(1/4)(7)=x
x\approx-1.40368
I suggest you use the exact form (the logarithm) to calculate the next step, instead of the approximation.

7^(2^x)=7^(2^(\log_(1/4)(7)))

\approx2.08649

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