Question #72ad1

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Answer 1 · 2017-09-29T15:07:44

#y'=3/4*csch(2x)#

1) I used #(Lnu)'#=#(u')/u# rule.

2) I used #(sechu)^2/tanhu=2csch(2u)# rule.

#y=3/4*ln[tanh(x/2)]#

#y'=3/4*1/2*[sech(x/2)]^2/tanh(x/2)#

#y'=3/8*[sech(x/2)]^2/tanh(x/2)#

#y'=3/8*1/(coshx*sinhx)#

#y'=3/8*1/(1/2*sinh(2x))#

#y'=3/4*csch(2x)#