Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Question #94009

1 Answer

Jan 7, 2017

$LHS=cot^3t/csct$

$=(cos^3t)/(sin^3tcsct)$

$=(cost*cos^2t)/sin^2t$

$=(cost*(1-sin^2t))/sin^2t$

$=cost*(1/sin^2t-sin^2t/sin^2t)$

$=cost*(csc^2t-1)=RHS$

Verified

Related questions

See all questions in Proving Identities

Impact of this question

1821 views around the world

You can reuse this answer
Creative Commons License