Question #6c534

Question

868 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-12T08:36:48

#RHS=1+(2cosx(1+cosx))/sin^2x#

#=1+(2cosx(1+cosx))/(1-cos^2x)#

#=1+(2cosx(1+cosx))/((1-cosx)(1+cosx))#

#=1+(2cosxcancel((1+cosx)))/((1-cosx)cancel((1+cosx)))#

#=1+(2cosx)/(1-cosx)#

#=(1-cosx+2cosx)/(1-cosx)#

#=(1+ucosx)/(1-cosx)=LHS#

Proved