A beaker whose mass was $345.8g$ was filled with a $225mL$ volume of carbon tetrachloride, to give a combined mass of $703.55*g$ . Given these data, what is $rho_"carbon tetrachloride"$ ?

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Answer 1 · 2016-12-17T04:54:03

$rho_"carbon tetrachloride"="Mass of carbon tetrachloride"/"Volume of carbon tetrachloride"$

And so we put the given numbers in:

$rho_"carbon tetrachloride"=(703.55*g-345.8*g)/(225*mL)=??g*mL^-1$

Because $1*g*mL^-1=1xx10^-3kg*(10^-3L)^-1=1xx10^-3kgxx10^3*L^-1=kg*L^-1$ , the $"density"$ has the same figures in $kg*L^-1$ .

$"Carbon tetrachloride"$ will form an immiscible layer with water. Will it float? How can you tell from these figures?

A beaker whose mass was 345.8*g345.8*g was filled with a 225*mL225*mL volume of carbon tetrachloride, to give a combined mass of 703.55*g703.55*g. Given these data, what is rho_"carbon tetrachloride"rho_"carbon tetrachloride"?