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Question #23ee5

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Dec 18, 2016

#LHS=(sin4theta)/sintheta#

#=(2sin2thetacos2theta)/sintheta#

#=(4sinthetacosthetacos2theta)/sintheta#

#=4costheta(2cos^2theta-1)#

#=8cos^3theta-4costheta=RHS#

Proved

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