Question

Question #e1aae

Answer 1

`f'(x)=xsec^2x+tanx`

Explanation:

differentiate using the `color(blue)"product rule"`

`"Given " f(x)=g(x)h(x)" then"`

`color(red)(bar(ul(|color(white)(2/2)color(black)(f'(x)=g(x)h'(x)+h(x)g'(x))color(white)(2/2)|)))`

`"here "g(x)=xrArrg'(x)=1`

`"and " h(x)=tanxrArrh'(x)=sec^2x`

`rArrf'(x)=xsec^2x+tanx`