Prove? $cotx/(cscx-1)=(cscx+1)/cotx$

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Answer 1 · 2017-01-17T04:39:58

Remember that $1+cot^2x=csc^2x$ .

$cotx/(cscx-1)=(cscx+1)/cotx$

Remember that $1+cot^2x=csc^2x$ . This becomes useful if we multiply the terms with $cscx$ to get them squared:

$cotx/(cscx-1)((cscx+1)/(cscx+1))=(cscx+1)/cotx$

$(cotxcscx+cotx)/(csc^2x-1)=(cscx+1)/cotx$

We can now use $csc^2x-1=cot^2x$

$(cotxcscx+cotx)/(cot^2x)=(cscx+1)/cotx$

$(cscx+1)/(cotx)=(cscx+1)/cotx$

Prove? cotx/(cscx-1)=(cscx+1)/cotxcotx/(cscx-1)=(cscx+1)/cotx