What is the derivative of $sin x - \frac{x}{2}$ $sinx-x/2$ ?

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Answer 1 · 2017-02-02T14:05:14

Split and Combine

The derivative of $sin (x) = cos (x)$ $sin(x) = cos(x)$
The derivative of $- \frac{1}{2} x = - \frac{1}{2}$ $-1/2x = -1/2$

So the final derivative of $y = sin (x) - \frac{x}{2}$ $y = sin(x)-x/2$ is:

$cos (x) - \frac{1}{2}$ $cos(x) - 1/2$

What is the derivative of sinx-x/2sinx−x2sinx-x/2?