Question #a5232

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Answer 1 · 2017-01-24T14:46:51

$LHS=sqrt((1+cos theta)/(1-cos theta))$

$=sqrt(((1+cos theta)(1+costheta))/((1-costheta)(1+cos theta)))$

$=sqrt((1+cos theta)^2/((1-cos^2theta))$

$=sqrt((1+cos theta)^2/sin^2theta)$

$=(1+cos theta)/sintheta$

$=1/sintheta+cos theta/sintheta$

$=csctheta+cottheta=RHS$

Proved