Question #4e7fa

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Question #4e7fa

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Answer 1 · 2017-01-27T08:37:41

$0 <=theta<=pi/3 and 5/3 pi<=theta<=2 pi$

Explanation:

$r=3 cos theta and r=2-cos theta$ .

$3 cos theta =2-cos theta$
$4 cos theta = 2$
$cos theta = 1/2$

$theta = pi/3 = 60^0 and 5/3pi = 300^0$ for $0 <= theta <= 2 pi$

If we plot a graph, we can find that the region cover the inside $r=3 cos theta$ and $r= 2-cos theta$ are $0 <=theta<=pi/3 and 5/3 pi<=theta<=2 pi$ for $0<=theta<=2 pi$

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Question #4e7fa

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