How do we differentiate $f(x)=tan^3x$ ?

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Answer 1 · 2017-03-29T16:04:30

Derivative is $3tan^2xsecx$

We can use chain rule here,

as if $f(x)=g(x)^3$ and $g(x)=tanx$ , therefore $f(x)=tan^3x$

Hence, $(df)/(dx)=(df)/(dg)xx(dg)/(dx)$

= $3(g(x))^2xxsecx$

= $3tan^2xsecx$

How do we differentiate f(x)=tan^3xf(x)=tan^3x?