How do you factor x^2-y^2-8x+16 ?

1 Answer
Feb 7, 2017

x^2-y^2-8x+16 = (x-y-4)(x+y-4)

Explanation:

The difference of squares identity can be written:

a^2-b^2=(a-b)(a+b)

We can use this with a=(x-4) and b=y as follows:

x^2-y^2-8x+16 = (x^2-8x+16)-y^2

color(white)(x^2-y^2-8x+16) = (x-4)^2-y^2

color(white)(x^2-y^2-8x+16) = ((x-4)-y)((x-4)+y)

color(white)(x^2-y^2-8x+16) = (x-y-4)(x+y-4)