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Question #c9664

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Feb 7, 2017

$LHS=tan(alpha+beta) cos(alpha+beta)$

$=sin(alpha+beta)/cos(alpha+beta)xx cos(alpha+beta)$

$=sinalphacosbeta+cosalphasinbeta$

$=(cscalphasecalpha(sinalphacosbeta+cosalphasinbeta))/(cscalphasecalpha)$

$=(cscalphasecalphaxxsinalphacosbeta+cscalphasecalphacosalphasinbeta)/(cscalphasecalpha)$

$=(secalphacosbeta+cscalphasinbeta)/(cscalphasecalpha)=RHS$

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